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28.STEP:1 O3 is in equilibrium with O2 & O with forward rate constant k1 an backward rate constant k2 (fast). STEP 2: O3 + O -> 2O2 (slow) rate constant k find order of the reaction |
| Answer» 28.STEP:1 O3 is in equilibrium with O2 & O with forward rate constant k1 an backward rate constant k2 (fast). STEP 2: O3 + O -> 2O2 (slow) rate constant k find order of the reaction | |