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28. If the sixth term of an AP is zero then show that its 33rd term is threeCBSE 2017]times its 15th term.29. The 4th term of an AP is 11. The sum of the 5th and 7th terms of this APICBSE 2015]is 34. Find its common difference.

Answer»

For question 28.a + 5d =0a=-5d (1)now LHS,a + 32 d = (32 - 5) d from (1)= 27dRHS,3(a + 14 d) = (14d - 5d) 3 = 9 x 3 d= 27d

LHS = RHSHence proved.



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