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28. If sin a.sin ß-cosa.cosB =1, show that tan a+tan B=0. |
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Answer» Answer: Hey BUDDY here's ur answer sinAsinB - cosAcosB = 1 <--- given cosAcosB - sinAsinB = -1 <--- multiplies both sides by -1 cos(A+B) = -1 <--- angle addition FORMULA for COSINE A+B is an odd multiple of pi <--- cosine function is -1 at 180=pi, 540 = 3*pi, 900=*5*pi, etc sin(A+B)=0 <-- SINE function is zero at odd multiples of pi sinAcosB + sinBcosA = 0 <--- angle addition formula for sine sinA/cosA + sinB/cosB = 0 <--- divides both sides by cosA*cosB tanA + tanB = 0 <--- TAN = sin/cos |
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