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।।।।||||।।27. यदि 4 sin° 0 = 3 और 0" < 0 <90°, तब 1 + COS 9 का मान मालूम करें ।।

Answer»

Sinx^2=3/4; Sinx=V3/2; Sinx^2+ cosx^×=1; (V3/2)^2-1= 3/4-1=3-4/4=1/4=1/2; V3/2=1+ 1/2

sinx^2+ cosx^2=1; (3/4)+ cosx^2=1; cosx^2=1-(3/4)=(4-3/4)=1/4; cosx=1/2; 1+cosx=1+1/2=2+1/2=3/2



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