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27. From a circular card sheet ofradius 14cm, two circles of radius7cm and a rectangle of length 2cmand beadth 1em is removed asshown in the adjointhis and answer the followingquestions1.what is the area of small circle?2.what is the area of rectangle?3.what is the area of two circle?4.what is the area of card sheet?5.what is the area of remaining sheet? |
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Answer» Radius of the CIRCULAR sheet= 14cm Area= \pi r^2=\frac{22}{7}\times14\times14cm^2πr 2 = 7 22
×14×14cm 2
=616cm^2=616cm 2
Area of 2 small circles= 2\pi r^2πr 2
=2\times\frac{22}{7}\times3.5\times3.5cm^2=2× 7 22
×3.5×3.5cm 2
=77.0cm^2=77.0cm 2
Area of the rectangle= l\times bl×b =3\times1cm^2=3cm^2=3×1cm 2 =3cm 2
Area of the remaining sheet after REMOVING the 2 circles and 1 rectangle =616cm^2-\ \left(77+3\right)cm^2=616cm 2 − (77+3)cm 2
=616cm^2-\ 80CM^2=536cm^2=616cm 2 − 80cm 2 =536cm 2 |
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