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26. Two ships are approaching a lighthouse from opposite directions. The angles ofdepression of the two ships from the top of the lighthouse are 30° and 45°. If thedistance between the two ships is 100 m, find the height of the lighthouse.[Use /3 = 1.732] |
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Answer» AB = 100Let AC = xLet BC = 100-xLet CD = hInΔEAD,EA = DCED = ACtan 45° = EA/ED1 = h/xx = hIn ΔDFBFB = CDDF = CBtan 30° = FB/DF1/√3 = h/100-x1/√3 = h/100-h100-h =√3h100-h = 1.732h2.732h = 100h = 100/2.732h = 36.603mh = 36.6m |
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