26 The 8th term of an AP is 31. If its 15th term exceeds its 11th term

1.	26 The 8th term of an AP is 31. If its 15th term exceeds its 11th term by 16, find t
Answer» since A.P series is like this a, (a+d), (a+2d), (a+3d), (a+4d), ……………………………. , {a+(n-1)d} and nth term is given by = {a+(n-1)d} so 8th term will be a+7d , 11th term will be a+10d and 15th term will be a+14d so as per qn. a+7d= 31 ……………… (1) & a+14d = a+10d +16 therefore 4d = 16 & d = 4 ……………….. (2) use by using (2) in (1) a + 7 *4 = 31 we get a = 31–28 = 3 so the required A.P will be 3, 7, 11, 15, 19, 23, Like my answer if you find it useful!

26 The 8th term of an AP is 31. If its 15th term exceeds its 11th term by 16, find t

Answer»

since A.P series is like this

a, (a+d), (a+2d), (a+3d), (a+4d), ……………………………. , {a+(n-1)d}

and nth term is given by = {a+(n-1)d}

so 8th term will be a+7d ,

11th term will be a+10d and

15th term will be a+14d

so as per qn.

a+7d= 31 ……………… (1)

& a+14d = a+10d +16

therefore 4d = 16

& d = 4 ……………….. (2)

use by using (2) in (1)

a + 7 *4 = 31

we get a = 31–28 = 3

so the required A.P will be 3, 7, 11, 15, 19, 23,

Like my answer if you find it useful!