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26. Evaluatesec 41°, sin 49+os49 cosec 41an 20 an 60 tan 70-3(cos 45-sin goe |
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Answer» sec41°sin49°+cos29°cosec61°-2/√3(tan20°tan60°tan70°)]/[3(sin²31°+sin²59°)]=[sec41°sin(90°-41°)+cos29°cosec(90°-29°)-2/√3{tan20°×√3×tan(90°-20°)}]/[3{sin²31°+sin²(90°-31°)]=[sec41°cos41°+cos29°sec29°-2(tan20°cot20°)]/[3(sin²31°+cos²31°]=(1+1-2)/(3×1)=0 |
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