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25 men can do a work in 10 days while working for 6 hours per day. If they work for 10 hours per day, then in how many days can 18 men do 3 times of that work?1. 36 days2. 25 days3. 31 days 4. 32 days |
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Answer» Correct Answer - Option 2 : 25 days Given: M1 = 25 D1 = 10 H1 = 6 M2 = 18 H2 = 10 W2 = 3 × W1 Formula Used: (M1 × D1 × H1)/W1 = (M2 × D2 × H2)/W2 Where M1 → Initial Men D1 → Initial day H1 → Initial hour M2 → Final men D2 → Final day H2 → Final hour Calculation: (M1 × D1 × H1)/W1 = (M2 × D2 × H2)/W2 ⇒ (25 × 10 × 6)/W1 = (18 × D2 × 10)/(3 × W1) ⇒ (25 × 10 × 6 × 3 × W1)/(18 × 10 × W1)= D2 ⇒ D2 = 25 ∴ The time taken by 18 men to do 3 times of that work while working 10 hours per day is 25 days. |
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