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25 In the figure Bo and Co are bisectors of interior ofBOC 90+BAC0.ZB and L C intersecting at O. Show that

Answer»

As we know A + B + C = 180So, B + C = 180 - AOr, (B/2) + (C/2) = 90 - (A/2) ....(1)

Now think in triangle BOC,we have three angles, OBC, BOC and OCBOBC = (B/2)OCB = (C/2)Let BOC = X

So, X + (B/2) + (C/2) = 180From equation (1)

X + 90 - (A/2) = 180X = 90 + A/2 (Proved !!!)



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