1.

24Arunrepayshisloan amount of1,18,000 by paying every month,starting with the first installment of .1000. If he increases theinstallment by .100 every month what amount will be paid as thelast installment of loan?.

Answer»

Loan Amount = Rs 118000

First installment = 1000Second installment = 1100Third installment = 1200

Thus loan installments form an AP with first digit a = 1000, common difference d = 100

Let number of installments are n to repay loan

Then,Sn = (2a + (n-1)d)n/2118000*2 = [2*1000 + (n-1)100]n1180*2 = n(20 + (n-1))2360 = 19n + n^2 n^2 + 19n - 2360 = 0n^2 + 59n - 40n - 2360 = 0n(n + 59) - 40(n + 59) = 0n = 40,-59Negative value not possible

So total number of installments are 40

Amount paid for last installment= 1000 + (39)*100= Rs 4900



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