247. Find the valu o(216) (256) (243)5 – InterviewSolution

1.	247. Find the valu o(216) (256) (243)5
Answer» (216)^1/3=6 and 6^2=36hence(216)^2/3=36(256)^1/4=4 and 4^3=64hence(256)^3)4=64(243)^1/5=3hence put in the given expression4/(36)^-1+1/(64)^-1+2/(3)^-1436+164+2*3=144+64+6=214

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