24)Solve 2 cos2 x + 3 sin x0 – InterviewSolution

1.

24)Solve 2 cos2 x + 3 sin x0

Answer»

2(1-sin^x) + 3sinx = 0-2sin^2x + 3sinx + 2 = 0

2sin^2x -3sinx - 2 = 0(2sinx + 1)(sinx - 2) = 0sinx = -1/2 or sinx =2 ---but sinx cannot = 2 so just work with -1/2

sinx = -1/2 quadrants III and IVx = 210 deg (or 7pi/6) + 2npi in QIIIx = 330 deg (or 11pi/6) + 2npi in QIV

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