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24 men working at 8 hours per day can do a piece of work in 15 days. In how many days can 20 men working at 9 hours per day do the same work? |
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Answer» M1D1H1 = M2D2H2 ∴ M1 = 24 D1 = 15 days H1 = 8 hrs M2 = 20 D2 = ? H2 = 9 hrs ⇒ 24 × 15 × 8 = 20 × x × 9 ⇒ x = (24 x 15 x 8)/(20 x 9) = 16 ∴ No. of days are required = 16 [ ∵ No. of men and working hours are in inverse] |
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