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24) Calculate the number of atoms of hydrogen present in 5.6 g of urea, (NHCO. Also calculate the number of atoms of N, C and o.​

Answer»

Na= 6.022×10^2343gm.......….. Na ATOMS 5.6 GM........Na×5.6/43 atoms of HExplanation:for N,C,O ALSO same H.= Na×5.6/43 atoms



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