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24. Calculate the amount of glucose required for preparing 500mL of 0.1M solution. IT |
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Answer» ong>ANSWER: we KNOW that molarity=given moles of SOLUTE÷total volume of solution in liters , 0.1=n solute÷500/1000 0.1=n solute/0.5l 0.1×0.5=n solute 0.05moles=solute now WEIGHT of solute =give moles ×gram atomic MASS of solute =0.05×180(gram atomic mass of glucose) =9ml of gulcose |
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