Saved Bookmarks
| 1. |
24. An AP consists of 50 terms of which 3"d tern is 12 and the last term is 106. Find the 29term. |
|
Answer» n=50 It is an AP. So, tn=a+(n-1)d t3=a+(3-1)d 12 =a+2d (1) Last term is 106. t50=a+(50-1)d 106=a+49d (2) From (1) and (2), 106=12-2d+49d 94=47d d=94/47 =2 a= 12-2d =12-2(2) =8 a=8 So t29=a+(n-1)d =8+(29-1)2 =8+28(2) =8+56 =64. |
|