23g of sodium will react with methyl alcohol to give

1.	23g of sodium will react with methyl alcohol to give
Answer» one mole of oxygen `22.4 dm^(3)` of hydrogen as at N.T.P 1 mole of `H_(2)` 11.2 L of hydrogen gas at N.T.P Solution :`{:(CH_(3)OH+NA,rarr,CH_(3)ONA,+(1)/(2)H_(2)),("" 23g,,,((1)/(2)mol)),(""(1 mol),,,):}` `23g` of `Na -= 1 mol Na -= (1)/(2) mol H_(2)` `= (1)/(2) xx 22.4 = 11.2 L` of `H_(2)` at N.T.P.

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