23892U is known to undergo radioactive decay to form 20682Pb by emitti – InterviewSolution

1.	23892U is known to undergo radioactive decay to form 20682Pb by emitting alpha and beta particles. A rock initially contained 68×10−6 g of 23892U. If the number of alpha particles that it would emit during its radioactive decay of 23892U→20682Pb in three half-lives is Z×1018, then what is the value of Z?
Answer» $_{92}^{238} U$ is known to undergo radioactive decay to form $_{82}^{206} P b$ by emitting alpha and beta particles. A rock initially contained $68 \times 10^{- 6} g$ of $_{92}^{238} U .$ If the number of alpha particles that it would emit during its radioactive decay of $_{92}^{238} U \to_{82}^{206} Pb$ in three half-lives is $Z \times 10^{18}$ , then what is the value of $Z$ ?

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