23 g sodium metal reacts with water. Calculate the : (a) volume of H2

1.	23 g sodium metal reacts with water. Calculate the : (a) volume of H2 liberated at NTP, (b) moles of H2 liberated, (c) weight of H2 liberated.
Answer» The given reaction is, 2Na + 2H₂ O ----> 2NaOH + H₂ From equation, it is evident: 46 g Na reacts to liberate 1 mole H₂, 23 g Na reacts to liberate (1 x 23)/46 = 1/2 mole H₂ Weight of H₂ liberated = (1/2) x 2 = 1 g Also, volume of H₂ at STP = 22400 x 1/2 = 11200 mL

23 g sodium metal reacts with water. Calculate the : (a) volume of H2 liberated at NTP, (b) moles of H2 liberated, (c) weight of H2 liberated.

Answer»

The given reaction is,

2Na + 2H₂ O ----> 2NaOH + H₂

From equation, it is evident:

46 g Na reacts to liberate 1 mole H₂,

23 g Na reacts to liberate (1 x 23)/46 = 1/2 mole H₂

Weight of H₂ liberated = (1/2) x 2 = 1 g

Also, volume of H₂ at STP = 22400 x 1/2 = 11200 mL