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.^(226)Ra disintegrates at such a rate that after 3160 years only one fourth of its original amount remains. The half-life of .^(226)Ra will be |
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Answer» 790 years `N = N_(0) ((1)/(2))^(n)...(i), t = n XX t_(1//2)` ...(ii) For `RA^(226) (N)/(N_(0)) = (1)/(4)`, from eq. (i) `(1)/(4) = ((1)/(2))^(n) or ((1)/(2))^(n) or ((1)/(2))^(2) = ((1)/(2))^(n) , n = 2`, from eq. (ii) `T_(1//2) = (t)/(n) = (3160)/(2) = 1580 yrs` |
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