221 flask contains 1.4 g N2 and 1.0 g H2. What would be the ratio of a

1.	221 flask contains 1.4 g N2 and 1.0 g H2. What would be the ratio of active mass of N2 and H2 ?
Answer» Answer: Ratio of O2 : N2 by weight=1:4. Let the weight of O2= 1 gm. The weight of N2=4 gm. The ratio of the No. Of MOLECULES will be the ratio of the Number of their moles ie., = 1/32 :4/28 = 28: (4 x32) = 7 : 32 = 7:3

221 flask contains 1.4 g N2 and 1.0 g H2. What would be the ratio of active mass of N2 and H2 ?

Answer»

Answer:

Ratio of O2 : N2 by weight=1:4.

Let the weight of O2= 1 gm.

The weight of N2=4 gm.

The ratio of the No. Of MOLECULES will be the ratio of the Number of their moles ie.,

= 1/32 :4/28

= 28: (4 x32) = 7 : 32

= 7:3