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| 1. |
22 of trigonometry in exercise 3.2 |
| Answer» Cot (3x)=cot (2x+x)=>cot3x =(cot 2x cotx -1)÷(cot2x+cotx) [by cot(x+y)formula]=>cot3x (cot2x+cotx)=cotx cot2x -1=>cot3x cot2x + cot3x cotx =cotx cot2x -1=>cotx cot2x - cot3x cot2x - cot3x cotx =1=>LHS | |