1.

22 g of CO_(2) contains ……….. molecules of CO_(2).

Answer»


SOLUTION :44 g of `CO_(2)` contains `6.023 xx 10^(23)` molecules.
`:.`22 g of `CO_(2)` will contain = `(6.023xx10^(23))/44xx22 = 3.0115 xx 10^(23)`


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