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22. Construct a quadrilateral PQRS in which PQ = 7.2 cm. QR = 6.4 cm. ZPQR = 90 PRS= 1204 and RS = 4.5 cm. (write the steps of construction) |
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Answer» ONG>Step-by-step explanation:P> Construct a line segment PR = 6.5 cm. (ii) Taking P as centre and 4.5 cm RADIUS and R as centre and 6 cm radius construct arcs which intersect each other at Q. (iii) Now join PQ and QR. (iv) Taking P as centre and 5 cm radius and R as centre and 5.5 cm radius, construct arcs which intersect each other at S. (v) Join PS and SR. Hence, PQRS is the required quadrilatera |
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