22= 2 x x 1.4 (1.4 + 15)= 2 × 22 × 0.2 (16.4)= 144.32 m27Example 10:

1.	22= 2 x x 1.4 (1.4 + 15)= 2 × 22 × 0.2 (16.4)= 144.32 m27Example 10: The diameter of a roller is 2.5 m and its length is 1.4 m. How much area vover in 7 revolutions?Radius of the roller (cylinder) =-mLength of the rollerCurved surface area of rollerolution:= 1.4m= 2trh22 2.5= 2×ー×ー×1,4 = 11m2We know that-Area covered in one revolution-Curved surface area of rollerTherefore
Answer» Radius of the roller (cylinder) = d/2 Length of the roller = 1.4m Curved surface area of the roller = 2πrh = 2 × 22/7 × 2.5/2 × 1.4 = 11 m² We know that, Area covered in one revolution = Curved surface area Therefore, Area covered in 7 revolution = 7 × Curved surface area = 7 × 11 = 77 m² Hence, the roller will cover 77m² in 7 revolution.

22= 2 x x 1.4 (1.4 + 15)= 2 × 22 × 0.2 (16.4)= 144.32 m27Example 10: The diameter of a roller is 2.5 m and its length is 1.4 m. How much area vover in 7 revolutions?Radius of the roller (cylinder) =-mLength of the rollerCurved surface area of rollerolution:= 1.4m= 2trh22 2.5= 2×ー×ー×1,4 = 11m2We know that-Area covered in one revolution-Curved surface area of rollerTherefore

Answer»

Radius of the roller (cylinder) = d/2

Length of the roller = 1.4m

Curved surface area of the roller = 2πrh

= 2 × 22/7 × 2.5/2 × 1.4

= 11 m²

We know that, Area covered in one revolution = Curved surface area

Therefore, Area covered in 7 revolution = 7 × Curved surface area

= 7 × 11 = 77 m²

Hence, the roller will cover 77m² in 7 revolution.