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21. Find the number of three-digit natural numbers which are divisible b2. The nth term of an AP is given by (-4n 15). Find the sum of first 20 terms of this A.P. (-540) |
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Answer» irst three digit no. which is divisible by 11 is 110 So, a(first term)=110 d(common difference)=11 an(last term)=990 an=a+(n-1)d990=110+(n-1)11 990-110=(n-1)11 880/11=(n-1) 80=n-1 n=81 So the no. of three digits divisible by 11 are 81 |
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