1.

21. Find the number of three-digit natural numbers which are divisible b2. The nth term of an AP is given by (-4n 15). Find the sum of first 20 terms of this A.P. (-540)

Answer»

irst three digit no. which is divisible by 11 is 110

So,

a(first term)=110

d(common difference)=11

an(last term)=990

an=a+(n-1)d990=110+(n-1)11

990-110=(n-1)11

880/11=(n-1)

80=n-1

n=81

So the no. of three digits divisible by 11 are 81



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