Saved Bookmarks
| 1. |
200cc of ozone diffused in 15 min through a porous membrane. How much time does 150cc of oxygen take to difffuse, under similar conditions ? |
|
Answer» Solution :`(V_(O_3) xx t_(O_2))/( V_(O_2) xx t_(o_3)) = sqrt((M_(o_2))/(M_(O_3)))= >( 200 xx t_(o_2))/( 150 xx 15 ) = sqrt((32)/(48))` `t_(O_2) = ( 15 xx 150 )/(200) =sqrt((32)/(48))=9.135 ` MIN |
|