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20 ml of hcl sol require 19.85 ml of 0.01M naoh sol for complete neutralisation the molarity of hcl sol is |
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Answer» The EQUATION for thereaction is: HCl + NaOH = NACL + H2O Mole ratio HCl : NaOH = 1:1
No. of MOLES of NaOH =No. of moles of HCl
No. of moles of NaOH =Volume in LITRES X molarity
= (19.85/1000) x 0.01 = 0.0001985 moles
No. of moles of HCl =Volume in litres x molarity 0.0001985 = (20/1000)x molarity
Molarity of HCl = 0.0001985/0.02
= 0.009925 M Approximately: = 0.01M
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