20 mL of HCl having a certain normality neutralises exactly 1.0 g CaCO_(3) . The normality of acid is

20 mL of HCl having a certain normality neutralises exactly 1.0 g CaCO

1.	20 mL of HCl having a certain normality neutralises exactly 1.0 g CaCO_(3) . The normality of acid is
Answer» 0.5 N 0.12 N 0.01 N 1.0 N Solution :`underset((100 g))(CaCO_(3)) + underset((73 g))(2HCl) to CaCl_(2) + H_(2)O + CO_(2)` is 100 g of `CaCO_(3)` shall be NEUTRALISED by `(73)/(100)=0.73 g ` HCl `therefore 20` mL of HCl has HCl in equivalent `=(0.73)/(36.5)` Hence Normality `=(0.73)/(36.5)XX(1000)/(20)=1.0 N`