20 ml of 0.1 m h2so4 is added to 30 ml of 0.2 m nh4oh then calculate ph of resultant solution . (given that pkb of nh4oh is 4.7)

20 ml of 0.1 m h2so4 is added to 30 ml of 0.2 m nh4oh then calculate p

1.	20 ml of 0.1 m h2so4 is added to 30 ml of 0.2 m nh4oh then calculate ph of resultant solution . (given that pkb of nh4oh is 4.7)
Answer» of the SOLUTION will be 9.777Explanation : we know that pH of a solution is given by;pH = 14-[pkb +LOG(acid/base)]moles equivalent of H₂SO₄ = 20 X 0.1 = 2moles equivalent of NH₄OH = 30 x 0.2 = 6=> pH = 14 - [ 4.7 + log(2/6)]=> pH = 14 - [ 4.7 - log3]=> pH = 14 - [ 4.7 -0.477 ]= 14 - 4.223=> pH = 9.777Hence the pH of the solution will be 9.777