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20 liter of tap water that hasCa(HCO3)2 was treated with 90 ml of M/50 HCl. The resulting solution requires an extra 6 ml of 0.1 M NaOH to make the solution neutral. What is the total hardness as parts of CaCO3 in ppm? (Take the molar mass of Ca(HCO3)2 = 162 g/mol) |
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Answer» 20 liter of tap water that hasCa(HCO3)2 was treated with 90 ml of M/50 HCl. The resulting solution requires an extra 6 ml of 0.1 M NaOH to make the solution neutral. What is the total hardness as parts of CaCO3 in ppm? (Take the molar mass of Ca(HCO3)2 = 162 g/mol) |
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