20 gm of CaCO_(3)is allowed to dissociate in a 5.6 litres container at 819^(@) C. If 50% of CaCO_(3) is dissocitated at equilibrium the 'K_(p)' value is

20 gm of CaCO_(3)is allowed to dissociate in a 5.6 litres container at

1.	20 gm of CaCO_(3)is allowed to dissociate in a 5.6 litres container at 819^(@) C. If 50% of CaCO_(3) is dissocitated at equilibrium the 'K_(p)' value is
Answer» <P>5 atm 1.6 atm 4.8 atm 10 atm Solution : Molar con. at EQULIBRIUM - `(X)/(5.6)` Given x=50% of 0.2 =0.1, `K_(c)=(CO_(2)]=(x)/(5.6)=(0.1)/(5.6)` but `K_(P)=K_(c)(RT)^(Delta N)=(0.1)/(5.6) xx (0.0821 xx 1092)^(1)=1.6` atm