20 gm ice at −10 ∘C is mixed with m gm steam at 100 ∘C. The minimum value of m so that finally all ice and steam converts into water is [ Use, specific heat and latent heat as Cice=0.5 cal/gm ∘C,Cwater=1 cal/gm ∘C,Lmelt =80 cal/gm and Lvapor =540 cal/gm ]

20 gm ice at −10 ∘C is mixed with m gm steam at 100 ∘C. The mini

1.	20 gm ice at −10 ∘C is mixed with m gm steam at 100 ∘C. The minimum value of m so that finally all ice and steam converts into water is [ Use, specific heat and latent heat as Cice=0.5 cal/gm ∘C,Cwater=1 cal/gm ∘C,Lmelt =80 cal/gm and Lvapor =540 cal/gm ]
Answer» $20 gm$ ice at $- 10^{\circ} C$ is mixed with $m gm$ steam at $100^{\circ} C$ . The minimum value of $m$ so that finally all ice and steam converts into water is $[$ Use, specific heat and latent heat as $C_{i c e} = 0.5 cal/gm^{\circ} C, C_{water} = 1 cal/gm^{\circ} C, L_{m e l t}$ $= 80 cal/gm$ and $L_{v a p o r}$ $= 540 cal/gm$ $]$

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20 gm ice at −10 ∘C is mixed with m gm steam at 100 ∘C. The minimum value of m so that finally all ice and steam converts into water is [ Use, specific heat and latent heat as Cice=0.5 cal/gm ∘C,Cwater=1 cal/gm ∘C,Lmelt =80 cal/gm and Lvapor =540 cal/gm ]

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