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20 dm^(3) of of SO_(2) diffuse through a porous partion in 60 s. What volume of will diffuse under similar conditions in 30s ? |
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Answer» Solution :`r_(SO_(2))=(20 dm^(3))/(60 s)=(1)/(2) dm^(3)s^(-1),r_(O_(2))=(v dm^(3))/(30 s)=(v)/(30)dm^(3)s^(-1)` Appying GRAHAM's law of diffusion, `(r_(O_(2)))/(r_(SO_(2)))=sqrt((M_(SO_(2)))/(M_(O_(2)))), i.e., (v//30)/(1//3)=sqrt((64)/(32))"or" (v)/(10)=sqrt(2)=1.414 "or" v=14.14 dm^(3)` |
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