1.

20.0 g of a magnesium carbonate sample decomposes on heating to give carbon dioxide and8.0 g magnesium oxide. What will be the percentage of purity of magnesium carbonate in the sample?

Answer»

60
84
75
96

Solution :`MgCO_(3) overset(Delta)(to) MgO + CO_(2)UARR`
84 g of `MgCO_(3)`gives 40 g of MgO. (100% purity)
20g of `MgCO_(3)` will give `=(40xx20)/84=9.52g`
9.52g of MgO is given by 100% pure `MgCO_(3)`.
8.0 g of MgO will be given by=`(100xx8)/9.52=84.03%`


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