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2 years ago a man was 5 times has old as his son 2 years later his age will be 8 more than 3 times has old as son.find their present ages |
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Answer» Let son's age today is x two YEARS ago son's age will be x-2 two years ago father's age will be 5(x-2) two years later son's age will be x+2 two years later father's age will be 3x+8+2 now, x-2 + 5(x-2) = x+2 + 3x+8+2 x-2 + 5x - 10 = 4x + 12 6x -12 = 4x +12 2x = 24 x = 12 son's present age is 12 fathers present age is 5(x-2) + 2 = 5 (12-2) +2 = 52 |
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