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2) x² + 2x - 5 = 0457272 +9y + 10 = 0 | |
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Answer» x² + 2X - 5 = 0 So, we have to find to it's zeroes by USING completing Square method. x² + 2x - 5 = 0 we can write 2x = 2(x)(1) x² + (2)(x)(1) + [ 1² - 1²] - 5 = 0 (x + 1)² - 1 - 5 = 0 [(x² + 2x + 1) = (x + 1)² , where, (a² + b² + 2ac = (a + b)²] so, (x + 1)² = 6 [taking Square Root both SIDE] (x + 1) = ±√6 ( 1 ) we have to take (+ve) sign. So, answeer will be. (x + 1) = √6 x = (√6 - 1) ( 2 ) we have to take (+ve) sign. So, answeer will be. (x + 1) = -√6 x = -(√6 + 1) |
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