1.

2^x-3×3^2x-8=36 find the value of x​

Answer»

Answer:

2

x−3

×3

2x−8

=4×9

2

x−3

×3

2x−8

=2

2

×3

2

2

x−5

×3

2x−10

=1

x=5

as RHS is 1, the POWERS have to be zero on the LHS as ANYTHING raise to 0 is ALWAYS 1

Thus x−5=0→x=5


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