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2. Write the outer electronic configuration of the following using orbital notationmethod. Justify.A. Ge (belongs to period 4 and group 14)B. Po (belongs to period 6 and group 16)C. Cu (belongs to period 4 and group 11) |
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Answer» Ge = Po = CU = EXPLANATION:ATOMIC number of Ge = 32Outer ELECTRONIC CONFIGURATION of Ge is-Ge = Atomic number of Po = 84Outer electronic configuration of Po is-Po = Atomic number of Cu = 29Outer electronic configuration of Cu is-Cu = |
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