2+under root 3 by 2-under root 3 + 2-under root 3 by 2+ under root 3

1.	2+under root 3 by 2-under root 3 + 2-under root 3 by 2+ under root 3
Answer» ANSWER: Step-by-step explanation: $\frac{2+\sqrt{3}}{2-\sqrt{3}}+\frac{2-\sqrt{3}}{2+\sqrt{3}}\\= \frac{(2+\sqrt{3})^2+(2-\sqrt{3})^2}{(2+\sqrt{3})(2-\sqrt{3})}\\=\frac{4+2\sqrt{3}+3+4-2\sqrt{3}+3}{2^2-\sqrt{3}^2}\\=\frac{14}{4-3}\\=14$ please CLICK on THANKS and rate 5 star PEACE!

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Step-by-step explanation:

$\frac{2+\sqrt{3}}{2-\sqrt{3}}+\frac{2-\sqrt{3}}{2+\sqrt{3}}\\= \frac{(2+\sqrt{3})^2+(2-\sqrt{3})^2}{(2+\sqrt{3})(2-\sqrt{3})}\\=\frac{4+2\sqrt{3}+3+4-2\sqrt{3}+3}{2^2-\sqrt{3}^2}\\=\frac{14}{4-3}\\=14$

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2+under root 3 by 2-under root 3 + 2-under root 3 by 2+ under root 3

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