2 two pendulums whose length differ by 22 cm oscillated at the same place so that one of them Max 30 oscillation and there other 36 oscillation during same time. find the length of the pendulum.

2 two pendulums whose length differ by 22 cm oscillated at the same pl

1.	2 two pendulums whose length differ by 22 cm oscillated at the same place so that one of them Max 30 oscillation and there other 36 oscillation during same time. find the length of the pendulum.
Answer» e...here is your answer...Here in this case the solution is as follows :t / 30 = 2\pi ROOT l / 9 and t / 36 = 2\pi root l - 22 / 9therefore, t / 30 X 36 / t = 2\pi root 1 / 9 x 1 / 2\pi root 9 / l - 22so, l = 72 cm.so second length 72 - 22 = 50 cm.hope it helps...

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2 two pendulums whose length differ by 22 cm oscillated at the same place so that one of them Max 30 oscillation and there other 36 oscillation during same time. find the length of the pendulum. ​

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2 two pendulums whose length differ by 22 cm oscillated at the same place so that one of them Max 30 oscillation and there other 36 oscillation during same time. find the length of the pendulum.