2.The sum of three numbers is 64. The second number is 3 less than the

1.	2.The sum of three numbers is 64. The second number is 3 less than the first number, the third is 11 less than twice the first. What are the numbers?
Answer» Step-by-step explanation: LET the FIRST number be x According to the question second number=x-3 third number=2x-11 x+(x-3)+(2x-11)=64 4x-14=64 4x=64+14 4x=78 x=78/4 x=19.5 therefore the first number is 19.5 second number is 19.5-3=16.5 third number is (2*19.5)-11=28 so the THREE numbers are 19.5,16.5and 28.

2.The sum of three numbers is 64. The second number is 3 less than the first number, the third is 11 less than twice the first. What are the numbers?

Answer»

Step-by-step explanation:

LET the FIRST number be x

According to the question

second number=x-3

third number=2x-11

x+(x-3)+(2x-11)=64

4x-14=64

4x=64+14

4x=78

x=78/4

x=19.5

therefore the first number is 19.5

second number is 19.5-3=16.5

third number is (2*19.5)-11=28

so the THREE numbers are 19.5,16.5and 28.

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2.The sum of three numbers is 64. The second number is 3 less than the first number, the third is 11 less than twice the first. What are the numbers?

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