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2. The moment of ineritia of an obfect aboutam aris in 200kg-m2. What is the reduisgyreation of the object about the anis?Weight of the object in 19.6N.​

Answer»

TOPIC :- Rotational Dynamics

\maltese\:\underline{\sf AnsWer :}\:\maltese

  • Moment of inertia (I) = 200 kg-m²
  • Weight of the object (F) = 19.6 N
  • Radius of gyration (K) = ?

To calculate the radius of gyration about an axis we will use the GIVEN below formula :

:\implies I \sf = MK^2 \\

But here first we need to find the mass of the object. So, LET's first find the mass of the object

\longrightarrow\:\:\sf F = mg \\

\longrightarrow\:\:\sf m =  \dfrac{F}{g} \\

\longrightarrow\:\:\sf m =  \dfrac{19.6}{9.8} \\

\longrightarrow\:\: \underline{ \boxed{\sf m =  2 \: kg}} \\

Hence, the mass (M) of the object is 2 kg. Now, let's find the radius of gyration (K).

:\implies I \sf = MK^2 \\

:\implies  \sf200 = 2 \times K^2 \\

:\implies  \sf K^2 =  \dfrac{200}{2}  \\

:\implies  \sf K^2 = 100\\

:\implies  \sf K =  \sqrt{100} \\

:\implies \underline{ \boxed{\sf K =  10 \: m}}



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