2. Ten years ago, A's age was half of B's age. If the ratio of their p

1.	2. Ten years ago, A's age was half of B's age. If the ratio of their present ages is 3:4, what will be the sum of their present ages ?
Answer» Answer: 35 YEARS Step-by-step explanation: B/Q:- 3x-10= 1/2(4x-10) 2(3x-10)= 2x-5 3x-10= 2x-5 x= -5+10 x= 5 A's age= 3X5= 15 B's age= 4X5= 20 Sum of their ages= 15+20= 35 years.

2. Ten years ago, A's age was half of B's age. If the ratio of their present ages is 3:4, what will be the sum of their present ages ?

Answer»

Answer:

35 YEARS

Step-by-step explanation:

B/Q:-

3x-10= 1/2(4x-10)

2(3x-10)= 2x-5

3x-10= 2x-5

x= -5+10

x= 5

A's age= 3X5= 15

B's age= 4X5= 20

Sum of their ages= 15+20= 35 years.