Saved Bookmarks
| 1. |
(2) tan 11+ tan+.. -o tan3 (b) tan() tan4-1-1(a) tan 3 (b) tan |
|
Answer» no wait... tan^-1(1) + tan^-1(1/2) + ....... = π/2 => π/4 + tan^-1(1/2) + ...... = π/2=> tan^-1(1/2) + ....... = π/2 -π/4 = π/4=> tan^-1(1/2) + tan^-1(x) = π/4=> (1/2+x)/(1-x/2) = tan(π/4)=> (1+2x)/(2-x) = 1=> (1+2x) = (2-x)=> 3x = 2-1=> x = 1/3 so, tan^-(1/3) is the answer. |
|