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2. Solve the following equations.(0)(x | 2x + 6 0, x E Z(ii) (x 5x + 16 1, X E N(iv) (x | 4x - 25> 13, x E Z(ii) (x | 2x 3 7, x e WIlI) 1X(V) y 1-7 s 13, y is a prime number |
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Answer» 1) 2x +6 = 0 and x belongs to Z(integers) so solving 2x+6 = 0 => x = -3.2) 5x+16 = 1 => 5x=16-1 =15 => x = 15/5 = 3.3) 2x-3<7 , and x belongs to W so 2x<7+3 = 10 => 2x<10 => x < 5 therefore value of x is [0,5) 4) 4x-25> 13 => 4x> (25+13=38) => x > 38/4 => x > 9.5 , and since x=Z so rhe value is [10, infinity) 5) 5y/3 -7 <= 13 => 5y/3 <= 20 => y<= 12 and y is prime no. so values of y are 2,3,5,7 and 11. |
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