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2 sin axlim | â <xâ0{ sin bx |
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Answer» At x = 0, the value of the given function takes the form 0/0So we will diffrentiate itAcosax/bcosbxNow after putting limit It will be a/bPlease like the solution 👍 ✔️ yar dekh woh function yadh kar sinax/ax=1.then multiply ax/ax in numeretor and also bx/bx in denominator it will become in the form ax/bx cancel the x and result becomes a/b |
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