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2(sin^6theta+cos^6theta)-3(sin^4theta+cos^4theta) |
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Answer» Answer: = 2{(sin²θ)³+(cos²θ)³}-3{(sin²θ)²+(cos²θ)²} = 2{(sin²θ+cos²θ)³-3sin²θcos²θ(sin²θ+cos²θ)}-3{(sin²θ+cos²θ)²-2sin²θcos²θ} =2(1-3sin²θcos²θ)-3(1-2sin²θcos²θ) =2-6sin²θcos²θ-3+6sin²θcos²θ =-1 |
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