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(2*sin(68^circ))/cos(22^circ) - 2*1/(5*tan(75^circ))*cot(15^circ) - 3*tan(20^circ)*tan(40^circ)*tan(45^circ)*tan(50^circ)*tan(70^circ)/5 |
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Answer» 2 sin68/ cos 22+ 2 cot15/5tan75-3 tan45tan20tan40tan50tan70/5=2 sin(90-68)/ cos22 - 2 cot 15/5 tan(90-75)-3 tan45tan20tan40tan50tan70/5=2cos22/ cos22 - 2 cot15/5 cot15-3tan45tan20tan50tan70/5=2-2tan45tan20tan50tan70/5=2+1+1+1/5=5/5=1 1 is the correct answer of the given question |
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